Respuesta :

Answer:

No

Step-by-step explanation:

Identify the equation for the circle

[tex](x-h)^2+(y-k)^2=r^2\\(x-2)^2+(y-13)^2=5^2\\(x-2)^2+(y-13)^2=25[/tex]

Check if (2,-11) is a point on the circle

[tex](x-2)^2+(y-13)^2=25\\(2-2)^2+(-11-13)^2=25\\0^2+(-24)^2=25\\576\neq25[/tex]

Since both sides of the equation are not equal to each other, then (2,-11) is not a point on the circle.

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