Question

when chlorine is added to acetylene tetrachloroethane is formed How many grams of tetrachloroethane are ade if 15 liters of chlorine is used with excess C2H2

Answer 1

35.5 g of tetrachloroethane is added if 15 grams of chlorine is used with excess $C_2H_2$.

What is a balanced chemical equation?

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is  the same for both the reactants and the products.

Balanced chemical equation:

$2Cl_2 (g) + C_2H_2 (g)$ → $C_2H_2Cl_4(l)$

In your case, 2 moles of chlorine gas are needed to produce 1 mole of tetrachloroethane, which implies that there's a 2:1 mole ratio between the two.

Calculating the mass of tetrachloroethane.

$m$$C_2H_2Cl_4(l)$ = $15 g$ $Cl_2 (g)$ X $\frac{2 mol \;of \;Cl_2}{70 g \;Cl_2}$ X $\frac{1 mol \;of \;C_2H_2Cl_4(l)}{2 mol \;Cl_2}$ X $\frac{167.8 g \;C_2H_2Cl_4(l))}{1 mol \;C_2H_2Cl_4}$

$C_2H_2Cl_4(l)$ = $17.75 g$

$C_2H_2Cl_4(l)$ = $35.5 g$

Hence, 35.5 g of tetrachloroethane is added if 15 gram of chlorine is used with excess $C_2H_2$

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