Question

Fe2O3 (s) + 3CO (g) -----> 2Fe (l) + 3CO2 (g)

How many moles of Fe2O3 must react to produce 760 kg of Fe? (please tell me how you get the answer...)

Answer 1

The number of moles of  Fe₂O₃ that must react to produce 760 kg of Fe are 20.503

What are moles?

The mole is a SI unit of measurement that is used to calculate the quantity of any substance.

The reaction is $\rm Fe_2O_3 (s) + 3CO (g) ----- > 2Fe (l) + 3CO_2$

The mass of Fe is given 760 kg

The molar mass of Fe is 55.9 g/mol

To calculate the number of moles

$n = \dfrac{m}{M} \\\\n = \dfrac{760000}{55.9 g/mol} = 13,669$

Now, the ratio between Fe and O is 2 : 3

$\dfrac{13,669}{2} \times 3 = 20,503.5$

convert it into kg = 20.503 mol

Thus, the moles are 20.503 mol

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