The volume of a gas is 605 liters at 27.0°C and the new temperature is -3.0°C, so the resultant volume of the sample is 544.53L.
Relation between the volume and temperature of the sample of gas is represented by the ideal gas equation PV = nRT, and for the question required equation is:
V₁/T₁ = V₂/T₂, where
V₁ & T₁ are the initial volume and temperature of the gas.
V₂ & T₂ are the final volume and temperature of the gas.
On putting values from the question on the above equation and by converting temperature into Kelvin, we get
V₂ = (605)(270.15) / (300.15) = 544.53 L
Hence required volume of the sample is 544.53L.
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