Considering Gay-Lussac's law, a gas exerts a pressure of 4.00 atm at 1,092 K.
Gay-Lussac's law states that the pressure of a gas is directly proportional to its temperature: when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, gas pressure decreases.
Gay-Lussac's law can be expressed mathematically as follows:
[tex]\frac{P}{T}=k[/tex]
where P= pressure, T= temperature, k= Constant
This law states that the ratio of pressure to temperature is constant.
Studying an initial state 1 and a final state 2, it is fulfilled:
[tex]\frac{P1}{T1}=\frac{P2}{T2}[/tex]
In this case, you know:
Replacing in Gay-Lussac's law:
[tex]\frac{1 atm}{273 K}=\frac{4 atm}{T2}[/tex]
Solving:
[tex]T2\frac{1 atm}{273 K}=4 atm[/tex]
[tex]T2=\frac{4 atm}{\frac{1 atm}{273 K}}[/tex]
T2= 1,092 K
Finally, a gas exerts a pressure of 4.00 atm at 1,092 K.
Learn more about Gay-Lussac's law:
https://brainly.com/question/4147359
#SPJ1
