Question

Three elements, A, Q, and Z, have the molar masses indicated in the table below. Given a compound with a composition of 15.66% A and 84.34% Z by mass, what is the empirical formula of this compound? Remember to enter subscripts as normal numbers (ie H2O is entered as H2O) and to enter elements in the same order they were given.

element symbol molar mass
A 15.45 g/mol
Q 20.05 g/mol
Z 41.62 g/mol

Answer 1

The empirical formula of the compound containing 15.66% A and 84.34% Z as given from the question is AZ₂

Data obtained from the question

• A = 15.66%
• Z = 84.34%
• Empirical formula =?

How to determine the empirical formula

Divide by their molar mass

A = 15.66 / 15.45 = 1.014

Z = 84.34 / 41.62 = 2.026

Divide by the smallest

A = 1.014 / 1.014 = 1

Z = 2.026 / 1.014 = 2

Thus, the empirical formula of the compound is AZ₂

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