Question

what volume of a 0.25M solution can be prepared with 28.5g of k2s? (molar mass=110.26g)

Answer 1

Answer:

volume = 1.04 dm^3

Explanation:

Data:

volume = ?

Molarity, M = 0.25M

mass = 28.5g

Molar mass = 110.25g

Moles = ?

Solution:

First find number of moles,

 moles = mass in gram / molar mass

             = 28.5 / 110.25

              = 0.258

              ≈ 0.26 moles

Now,

          Molarity = $\frac{no. of moles}{volume in dm^3}$

So,

           Volume in dm^3 = $\frac{no. of moles}{molarity}$

                                       =  0.26 / 0.25

                         Volume  = 1.04 dm^3