a force of 50 N directed 30 degrees above the horizontal is applied to a 10 kg block at rest on a rough horizontal surface. what is the coefficient of kinetic friction between the block and the horizontalsurface if the acceleration of the block is 20 m/s^2

A force that acts among sliding parts is referred to as kinetic friction. A body moving on the surface is subjected to a force that opposes its progressive motion.

The given data in the problem is;

μ is the coefficient of kinetic friction=?

m is the mass of the block=10 kg

g is the acceleration due to gravity= 9.81 m/s²

Acceleration of block(a)=20 m/s²

Force (F)= 50 N

θ=30°

There are two forces to act on the block, one is the force directed while the other was the friction force opposing the motion.

From the newton's second law;

F= ma

F-f = ma

Fcos30°- μmg=ma

50cos 30°-μ× 10×9.81 =10 × 20

μ= 1.597

Hence, the coefficient of kinetic friction will be 1.597.

To learn more about the coefficient of kinetic friction, refer to;

https://brainly.com/question/19180015

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