The generator power will be 59 kW. Power drop is the main factor for finding the generated power.
The maximum power input allowed to pass through a piece of equipment is known as the equipment's power rating.
Power drop = 5%
The relation of the frequency change with the power drop is;
[tex]\rm \frac{df}{dp} =5\%\\\\ \frac{f_{rated-f_1}}{P_{rated}-P_1}=0.05\\\\ \frac{f_{rated-60}}{100-61}=0.05\\\\ f_{rated}=61.95[/tex]
For the grid frequency, 59.9 Hz
[tex]\rm \frac{f_{rated-f_2}}{P_{rated}-P_2}=0.05[/tex]
[tex]\rm \frac{61.95-f_2}}{100-P_2} =0.05\\\\ 100-P_2 =20(61.95-59.9)\\\\P_2=100-41 \\\\ P_2=59 \ kW[/tex]
Hence, the generator power will be 59 kW.
To learn more about the power rating, refer to the link;
https://brainly.com/question/13787703
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