3. A shuffleboard player applies a horizontal force of 10.0 N to the shuffleboard puck (400 g). If the puck accelerates at 24.5 m/s/s as the player continues to push it, what is the frictional force on the puck?

Respuesta :

Answer:

Friction = 2 N

Explanation:

F = ma

  = .4 * 24.5 = 9.8 N   net force      10 N by stick means Ffriction = 2 N

                                                                                                                   

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