Question

Which expresses this solution?

Answer 1

The equation that expresses the solution to the quadratic equation x² - 10x + 13 = 0 is $x =5 \pm 2\sqrt{3}$

How to express the solution?

The equation is given as:

x² - 10x + 13 = 0

The solution to a quadratic equation is represented by:

$x =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

So, we have:

$x =\frac{10 \pm \sqrt{(-10)^2 -4 * 1 * 13}}{2 * 1}$

Evaluate the radicand

$x =\frac{10 \pm \sqrt{48}}{2}$

Take the square root of 48

$x =\frac{10 \pm 4\sqrt{3}}{2}$

Divide

$x =5 \pm 2\sqrt{3}$

Hence, the equation that expresses the solution to the quadratic equation x² - 10x + 13 = 0 is $x =5 \pm 2\sqrt{3}$

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