The pH of the solution in which 4.85g of HCl is present is 1.3.
pH of the solution will be calculated by using the below equation:
pH = -log[H⁺]
Relation between the mass and moles of any substance will be represented as:
Moles of HCl = 4.85g / 36.4g/mol = 0.13 moles
Given volume = 2.5 L
Concentration in terms of molarity will be calculated as:
M = n/V
M = 0.13mol / 2.5L = 0.05 M
So, 0.05M HCl solution have the same amount of concentration of H⁺ ion. Now pH will be calculated as:
pH = -log(0.05) = 1.3
Hence required pH of the solution is 1.3.
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