A lady bug walked the shortest distance on the coordinate plane from point A(-1,-16) to point B(12, 10). Find the x-coordinate of the point where the ladybug intersected the x-axis

Respuesta :

(a) The shorted distance between point A and point B is 29.1.

(b) The x-coordinate of the point where the ladybug intersected the x-axis is (-1, 12).

Shortest distance between point A and point B

The shorted distance between point A and point B is straight line, which is calculated as follows;

[tex]d = \sqrt{(x_2-x_1)^2 + (y_2 - y_1)^2} \\\\d = \sqrt{(12--1)^2+ (10--16)^2} \\\\d = 29.1 \ unit[/tex]

x-coordinate of the points

The x-coordinate of the point where the ladybug intersected the x-axis is determined as;

(Ax, Ay), (Bx, By)

= (Ax, Bx)

= (-1, 12)

Learn more about distance between points here: https://brainly.com/question/7243416

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