Question

In a random sample of 74 homeowners in a city, 22 homeowners said they would
support a ban on nonnatural lawn fertilizers to protect fish in the local waterways. the sampling
method had a margin of error of +3.1%.

a) find the point estimate.

b) find the lower and upper limits and state the interval.

Answer 1

The point estimate is 29.73% and the lower and upper limits are 26.63% and 32.83% respectively.

What is the margin of error(MOE)?

It is defined as an error that provides an estimate of the percentage of errors in real statistical data.

The formula for finding the MOE:

$\rm MOE = Z\times \dfrac{s}{\sqrt{n}}$

Where   Z is the z-score at the confidence interval

            s is the standard deviation

            n is the number of samples.

Point estimate = 22/74 = 0.2973 = 29.73%

Lower limit = point estimate - MOE  = 29.73 - 3.1 = 26.63%

Upper limit = point estimate + MOE = 29.73 + 3.1 = 32.83%

Thus, the point estimate is 29.73% and the lower and upper limits are 26.63% and 32.83% respectively.

Learn more about the Margin of error here:

brainly.com/question/13990500

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