In a quadrilateral ABCD, the measure of the length of the quadrilateral CD will be 25.98 cm.
The connection between the lengths and angles of a triangular shape is the subject of trigonometry.
The length of AD will be
tan θ = AB/AD
AD = 12/ tan 35
AD = 17.14 cm
Then the value of the BD will be given by the Pythagoras.
BD² = AB² + AD²
BD² = 12² + 17.14²
BD² = 144 + 239.78
BD² = 437.78
BD = 20.92 cm
Then operate the sine rule in triangle BCD, we have
[tex]\dfrac{BD}{\sin C} = \dfrac{CD }{\sin B}\\\\\\\dfrac{20.92}{\sin 52} = \dfrac{CD }{\sin 102}\\\\\\CD = \dfrac{20.92 \times \sin 102}{\sin 52}[/tex]
On further solving, the value of CD will be
CD = 25.98
More about the trigonometry link is given below.
https://brainly.com/question/22698523
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