Question

1 start with 25°C and a volume of 10.0L. If I increase the volume to 15.0L, what is my new temperature? (Equation that is helpful: K= 273 + "C)

Answer 1

Answer:

If in volume of 10.0L it is 25°C than it will be 37.5C volume in the new temperature if increased from 10.0L to 15.0L

Explanation:

10.0L=25°C

15.0L=?

10×2.5= 25

15×2.5=37.5

Kelvin(K)= C+273=T

=37.5+275=312.5

=C=312.5-275

=C=37.5