The equation 3x²-5x-5 will have two solutions.
If the value of x in the given quadratic equation is a real number then the roots of the equation are real.
The discriminant of the equation will be calculated as:-
= 3x ²- 5x - 5
D = b² - 4ac
D = ( 5 )² - 4 x 3 x -5
D = 25 - ( -60 )
D = 85
Since the discriminant is positive then the equation will have real roots and the degree of the equation is 2 so it will have two solutions.
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