Question

Trapezoid defg is dilated according to the rule do,4(x,y) to form the image trapezoid d'e'f'g', which is shown on the graph. on a coordinate plane, trapezoid d prime e prime f prime g prime has points (negative 8, 8), (negative 3, 8), (negative 5, 4), and (negative 8, 4). what are the coordinates of point g of the pre-image? (-2, 1) (-4, 2) (-12, 0) (-32, 16)

Answer 1

Since the figure is dilated by a factor of 4, the coordinates of point g of the pre-image is (-2, 1)

How to determine the coordinates of point g?

The coordinates of the image are given as:

• d' = (-8,8)
• e' = (-3,8)
• f' = (-5,4)
• g' = (-8,4)

The dilation rule is given as:

(x,y) -> 4(x,y)

So, we have:

(-8,4) = 4 * g

Divide both sides by 4

g = (-2,1)

Hence, the coordinates of point g of the pre-image is (-2, 1)

Read more about dilation at:

https://brainly.com/question/3457976

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Answer 2

Answer:

A

Step-by-step explanation:

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