Question

On a coordinate plane, a circle has a center at (1, negative 2) and a radius of 4 units. which equation represents a circle with the same radius as the circle shown but with a center at (-1, 1)? (x – 1)2 (y 1)2 = 16 (x – 1)2 (y 1)2 = 4 (x 1)2 (y –1)2 = 4 (x 1)2 (y – 1)2 = 16

Answer 1

The equation of the circle of radius 4 and center at (-1, 1) is given as follows:

$(x + 1)^2 + (y - 1)^2 = 16$

What is the equation of a circle?

The equation of a circle of center $(x_0, y_0)$ and radius r is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

In this problem:

• The circle has center at (-1,1), hence $x_0 = -1, y_0 = 1$.

• The circle has radius r = 4.

Hence, the equation is given as follows:

$(x - (-1))^2 + (y - 1)^2 = 4^2$

$(x + 1)^2 + (y - 1)^2 = 16$

More can be learned about the equation of a circle at https://brainly.com/question/24307696

#SPJ4