The percent composition of Cesium and Fluorine in CsF are 87.493 % and 12.507 % respectively.
Percent composition is very simple. Percent composition tells you by mass what percent of each element is present in a compound.
Molecular mass of Cs = 132.9054519
Molecular mass of F = 18.9984032
Molecular mass of CsF = 132.9054519 + 18.9984032 = 151.9038551
CsF: Percent composition by element:
Cesium (Cs) = [tex]\frac{32.9054519 X 100}{151.9038551}[/tex] = 87.493 %
Fluorine (F) = [tex]\frac{18.9984032 X 100 }{151.9038551}[/tex]= 12.507 %
Hence, the percent composition of Cesium and Fluorine in CsF are 87.493 % and 12.507 % respectively.
Learn more about the percentage composition here:
https://brainly.com/question/20614202
SPJ1