Question

ASAP PLEASEE A certain amount of Argon has 2.4x10^24 atoms. Going backwards from Atoms to Grams, how many grams of Ar would that be?

Answer 1

The required mass of argon in given number of atoms of argon is 155.61 grams.

What is Avogadro's number?

Avogadro's number is the number of atoms which are present in 1 mole of any substance and it is equal to 6.022×10²³.

Relation between the mass and moles of any substance will be represented as:

• n = W/M, where
• W = given mass
• M = molar mass

So, moles of argon will be calculated by using given number of atoms as:

Moles = 2.4×10²⁴ atoms / 6.022×10²³ atoms per mole

Moles = 3.9 moles

Now mass will be:

W = (3.9mol)(39.9g/mol) = 155.61 g

Hence required mass of argon is 155.6g.

To know more about Avogadro's number, visit the below link:

https://brainly.com/question/1513182

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