Question

Which is the equation of a circle with a radius of 3 and a center at (0, 0) A . x ^ 2 + y ^ 2 = 3 B x ^ 2 + y ^ 2 = 6; x ^ 2 + y ^ 2 = 9 D. (x - 3) ^ 2 + (y - 3) ^ 2 = 0; (x + 3) ^ 2 + (y + 3) ^ 2 = 0

Answer 1

Answer:

x² + y² = 9

Explanation:

circle formula: (x -h)² + (y - k)² = r²

where (h, k) is the center, r is radius

Here given for center: (0, 0)

Identify

• h = 0

• k = 0

• r = 3

Equation of circle:

• (x - 0)² + (y - 0)² = 3²

• x² + y² = 9