Question

Help pls

Two digits of the 6-digit number X = 345 * 8* are missing. Fill in the missing digits
so that the number obtained is the smallest possible number that is divisible by 45.
Find X.

Answer 1

The smallest possible number that is divisible by 45 when the blanked place of the number is filled is 345285.

What is the divisible rule of 9 and 5?

The divisible rule of 9 and 5 are:

• Divisible rule of 9- When the addition of all number is divisible by 9, then that number also divisible by 9.
• Divisible rule of 5- When a number has a digit 0 or 5 in the last of it, then that number also divisible by 5.

Two digits of the 6-digit number are missing.

$X = 345 * 8*$

The smallest possible number from this is divisible by 45. The factors of 45 are 9 and 5.

$45=9\times5$

Thus, the 6-digit number which is divisible by 45, must be divisible by 9 and 5.  

To be divisible with 5, the number has 0 or 5 in last. So the numbers can be,

$X = 345 * 85\\X=345 * 80$

For first number, when the blank is filled with number 2 to make sum 9 and for second the blank number should be 7. Thus, the numbers,

$X = 345 285\\X=3457 80$

Thus, the smallest possible number that is divisible by 45 when the blanked place of the number is filled is 345285.

Learn more about the smallest common factor here;

https://brainly.com/question/16054958

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