The area of the face of a nickel 353.14 [tex]mm^{2}[/tex] (nearest hundredth)
The area of a circle is the amount of space enclosed within the boundary of a circle. The region within the boundary of the circle is the area occupied by the circle.
As the surface of nickel is in shape of 2-D circle.
radius of circle = [tex]\frac{21.21}{2}[/tex] = 10.605 mm
Area of circle= [tex]\pi r^{2}[/tex]
= 3.14* 21.21*21.21
= 353.143 [tex]mm^{2}[/tex]
= 353.14 [tex]mm^{2}[/tex] (nearest hundredth)
Thus, the area of the face of a nickel 353.14 [tex]mm^{2}[/tex] (nearest hundredth)
Learn more about area of circle here:
brainly.com/question/11952845
#SPJ1
