Question

sample of helium gas contains 0.22 moles of helium. How many additional moles of helium gas must be added to the sample to obtain a volume of 6.4L

Answer 1

The required additional moles of helium gas must be added to the sample to obtain a volume of 6.4L is 0.293 moles.

How do we calculate the required moles?

Required moles of the final volume will be calculated by using the below equation as:

n₁/V₁ = n₂/V₂, where

n₁ & V₁ are the moles and volume of initial solution.

n₂ & V₂ are the moles and volume of final solution.

On putting values from the question to the equation, we get

n₂ = (0.22)(6.4) / (4.8) = 0.293 moles.

Hence required moles of helium gas is 0.293.

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