Question

Answer for branliest!

Answer 1

Answer:

For the first question

$x = 2 \: cm$

For the second question

$x = 6 \: cm$

Step-by-step explanation:

To find the value if x in both equation we have to use the Pythagorean Theorem which states that:

${a}^{2} = {b}^{2} + {c}^{2}$

a being the hypothenus*

Therefore for the first question we know that

$a = x \: \: \: b = 1.6 \: \: \: \: c = 1.2 \\ so ... \: \: {x}^{2} = {1.6}^{2} + {1.2}^{2} \\ {x}^{2} = 2.56 + 1.44 \\ {x}^{2} = 4 \\ \sqrt{ {x}^{2} } = \sqrt{4} \\ x = 2$

For the second question we know that

$a = 6.5 \: \: \: b = 2.5 \: \: \: c = x \\ {6.5}^{2} = {2.5}^{2} + {x}^{2} \\ 42.25 = 6.25 + {x}^{2} \\ 42.25 - 6.25 = {x}^{2} \\ 36 = {x}^{2} \\ \sqrt{36} = \sqrt{ {x}^{2} } \\ 6 = x$