Question

Find the 97th term of the arithmetic sequence 25, 29, 33, ...25,29,33,...

Answer 1

If the first term is 25 and the common difference is 4. Then the 97th term of the sequence will be 409.

What is a sequence?

A sequence is a list of elements that have been ordered in a sequential manner, such that members come either before or after.

The sequence is given below.

25, 29, 33, ...., so on

Then the first term is 25. And the common difference is 4.

Then the 97th term will be given as

$\rm a_n = a + (n - 1)d$

where

n = 97

a = 25

d = 4

Then we have

a₉₇ = 25 + (97 - 1)4

a₉₇ = 25 + 96 x 4

a₉₇ = 25 + 384

a₉₇ = 409

Then the 97th term of the sequence will be 409.

More about the sequence link is given below.

https://brainly.com/question/21961097

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