Question

What is the equation of this line in standard form?

Answer 1

Based on the calculations, the equation of this line in standard form is equal to 6x - 11y = 13.

Given the following data:

• Points on x-axis = (1 1/2, -4) = (1.5, -4).

• Points on y-axis = (2, -1).

How to calculate an equation of a line?

Mathematically, the equation of a line in standard form is given by this formula:

y - y₁ = m(x - x₁)

Where:

• m is the slope.

• y is the point on the horizontal axis.

• x is the point on the vertical axis.

Next, we would determine the slope of this line:

$Slope = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}\\\\Slope = \frac{-1\;-\;2}{-4\;-\;1.5}\\\\Slope = \frac{-3}{-5.5}$

Slope = 6/11.

For the equation of this line, we have:

y - 2) = 6/11(x - 3/2)

y - 2 = 6x/11 - 9/11

11y - 22 = 6x - 9

6x - 11y = -9 + 22

6x - 11y = 13.

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Complete Question:

What is the equation of this line in standard form (1 1/2, 2) (-4, -1)?