Find the sum of the first 8 terms of the following series, to the nearest integer 48,60,75
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The series is a geometric series and the sum of the first 8 terms of the series 48, 60, 75 is 952.32
The series is given as:
48, 60, 75
The above series is a geometric series with the following parameters:
First term, a = 48
Common ratio, r = 1.25
The sum of n terms is:
[tex]S_n = \frac{a(r^n - 1)}{r -1}[/tex]
So, we have:
[tex]S_8 = \frac{48 * (1.25^8 - 1)}{1.25 -1}[/tex]
Evaluate
[tex]S_8 = 952.32[/tex]
Hence, the sum of the first 8 terms of the series is 952.32
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