Question

100 POINTS NEED ASAP
Determine the energy released per kilogram of fuel used.

Given MeV per reaction, calculate energy in joules per kilogram of reactants.
Consider 1 mole of plutonium-239 to be a mole of “reactions” (molar mass = 239 grams).

Answer 1

The energy released per kilogram of fuel used is mathematically given as  

energy release per kg= 6.702*10^{-13}. This is further explained below.

What is the energy released per kilogram?

Generally, is simply defined as

Energy used per person per year in US = 3-5 X 10^11

Population (No. of person)= 3.1x 10^8

Mass of feut required = 3.5x10^11 x3-1x10 8 x 10 )/6.703 X10^{13} kg

Mass of feut required = 1.62x10^{33}kg

Solution: Mev in Joule 6 = 10 1.60* I0^{-19} J

1 Mev= 1.602 X 10 T

energy release per kg= 1.602*10^{13}/2.39x10^{-3}

energy release per kg= 6.702*10^{-13}

In conclusion, Energy

energy release per kg= 6.702*10^{-13}

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