100 POINTS
Plutonium-235

Given: energy released = about 200 MeV per individual reaction (mass = 239 amu)

Part A
List the balanced nuclear reaction.
I NEED THIS ASAP

Respuesta :

Answer:

One gram atom of any substance contains one Avogadro number of atoms. Therefore, the number of atoms of U-235 present in 235 g of the substance = Avogadro Number = 6.02×10^23 atoms

The number of U-235 atoms present in 1 g of the substance = (6.02×10^23/235) atoms=2.56×10^21 atoms

Energy released in one atom fissioning = 200 MeV= 200 MeV × 1.6 × 10^-6 erg/MeV= 3.2 ×10^-4 erg/atom.

Energy released in the fission of all the atoms contained in 1g of Uranium-235 fissioning = (2.56×10^21 atom)×(3.2×10^-4 erg/atom)=8.19 ×10^17 erg

Now

1 kWh = 1000 Watt hour = 1000×( 10^7 erg/s)×3600s = 3.6 ×10^13 erg/kWh

So energy in kWh released in fission of 1 g of U-235 = (8.19× 10^17 erg)÷(3.6×10^13 erg/kWh) = 2.55 ×10⁴ kWh.

Added on 19th February, 2019.

The energy consumption of an average home in India in a month is between 300–500 kWh in the metropolitan cities. Let us take it at 400 kWh. So one gram of nuclear fuel (uranium) would be able to meet the energy requirements of a town of about 6000 for a month.

The energy in a fissile material is highly concentrated, compared to other types of fuels like wood, coal, diesel etc. So nuclear powered submarines can remain below water for very long periods of time, as they do not need to surface for getting fuel.

Explanation:

Energy in kWh released in fission of 1 g of U-235 is 2.55 ×10⁴ kWh.

How do find the energy released in fission?

One gram atom of any substance contains one Avogadro number of atoms. Therefore, the number of atoms of U-235 present in 235 g of the substance = Avogadro Number = 6.02×10^23 atoms

The number of U-235 atoms present in 1 g of the substance = (6.02×10^23/235) atoms=2.56×10^21 atoms

Energy released in one atom fissioning = 200 MeV= 200 MeV × 1.6 × [tex]10^{-6}[/tex] erg/MeV= 3.2 ×[tex]10^{-4}[/tex] erg/atom.

The energy released in the fission of all the atoms contained in 1g of Uranium-235 fissioning = (2.56×[tex]10^{21}[/tex] atom)×(3.2×[tex]10^{-4}[/tex] erg/atom) = 8.19 ×[tex]10^{17}[/tex] erg

1000 Watt hour = 1000×( [tex]10^{7}[/tex] erg/s)×3600s = 3.6 ×10^13 erg/kWh

So the energy in kWh released in fission of 1 g of U-235 = 2.55 ×10⁴ kWh.

Fission takes place when a neutron slams into a bigger atom, forcing it to excite and break up into smaller atoms—additionally referred to as fission products. Extra neutrons are also launched that may initiate a sequence reaction. whilst each atom splits, a high-quality amount of electricity is released.

Learn more about Fission here: brainly.com/question/4675347

#SPJ2

ACCESS MORE