Question

If log(16)=s, what is the value of 2/3 log(6400) - 1/3 log(1600) in terms of s?

Answer 1

The value of   $\dfrac{ 2}{3} log(6400) - \dfrac{1}{3} log(1600)$  in terms of s will be

$\dfrac{2}{3}(400s)-\dfrac{1}{3}(1000s)$

What is Logrithm?

A quantity representing the power to which a fixed number (the base) must be raised to produce a given number.

Here we have the expression:-

$\dfrac{ 2}{3} log(6400) - \dfrac{1}{3} log(1600)$

So in terms of s the expression will become:-

$\dfrac{2}{3}(400s)-\dfrac{1}{3}(1000s)$

To know more about logarithm follow

https://brainly.com/question/25710806

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