Work out the length of x
(The diagram is not drawn accurately)
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Answer:
x = 7
Step-by-step explanation:
using Pythagoras' identity in the right triangle.
the square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 24² = 25²
x² + 576 = 625 ( subtract 576 from both sides )
x² = 49 ( take square root of both sides )
x = [tex]\sqrt{49}[/tex] = 7
Hey ! there
Answer:
Step-by-step explanation:
In this question we are provided with a right angle triangle having hypotenuse 25 cm , base 24 cm and perpendicular x . And we are asked to find the length of x .
For finding the length of x we'll use Pythagorean Theorem . Pythagorean Theorem states that sum of square of perpendicular and base is equal to the square of hypotenuse in right angle triangle that is ,
[tex] \: \qquad \: \qquad \: \underline{\boxed{ \frak{H {}^{2} = P {}^{2} + B {}^{2} }}}[/tex]
Where ,
SOLUTION : -
Here in the triangle ,
Applying Pythagorean Theorem :
[tex] \quad \longmapsto \qquad \: (25) {}^{2} = (x ){}^{2} + (24) {}^{2} [/tex]
On squaring 24 and 24 we get ,
[tex] \quad \longmapsto \qquad \:625 = (x) {}^{2} + 476[/tex]
Subtracting 576 on both sides :
[tex] \quad \longmapsto \qquad \:625 - 576 = (x) {}^{2} + \cancel{ 576} - \cancel{576}[/tex]
We get ,
[tex] \quad \longmapsto \qquad \:49 = (x) {}^{2} [/tex]
Applying square root on both sides :
[tex] \quad \longmapsto \qquad \: \sqrt{49} = \sqrt{(x) {}^{2} } [/tex]
We get ,
[tex] \quad \longmapsto \qquad \: \blue{ \underline{\boxed{\frak{7 \: cm = x}}}} \quad \bigstar[/tex]
Verifying : -
We are verifying our answer by substituting all the values of hypotenuse , perpendicular and base in Pythagorean Theorem . So ,
Therefore, our answer is correct .