Respuesta :

Answer:

x = 7

Step-by-step explanation:

using Pythagoras' identity in the right triangle.

the square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + 24² = 25²

x² + 576 = 625 ( subtract 576 from both sides )

x² = 49 ( take square root of both sides )

x = [tex]\sqrt{49}[/tex] = 7

Hey ! there

Answer:

  • Length of x is 7 cm

Step-by-step explanation:

In this question we are provided with a right angle triangle having hypotenuse 25 cm , base 24 cm and perpendicular x . And we are asked to find the length of x .

For finding the length of x we'll use Pythagorean Theorem . Pythagorean Theorem states that sum of square of perpendicular and base is equal to the square of hypotenuse in right angle triangle that is ,

[tex] \: \qquad \: \qquad \: \underline{\boxed{ \frak{H {}^{2} = P {}^{2} + B {}^{2} }}}[/tex]

Where ,

  • H refers to Hypotenuse

  • P refers to Perpendicular

  • B refers to Base

SOLUTION : -

Here in the triangle ,

  • Hypotenuse is 25 cm

  • Base is 24 cm

  • Perpendicular is x

Applying Pythagorean Theorem :

[tex] \quad \longmapsto \qquad \: (25) {}^{2} = (x ){}^{2} + (24) {}^{2} [/tex]

On squaring 24 and 24 we get ,

[tex] \quad \longmapsto \qquad \:625 = (x) {}^{2} + 476[/tex]

Subtracting 576 on both sides :

[tex] \quad \longmapsto \qquad \:625 - 576 = (x) {}^{2} + \cancel{ 576} - \cancel{576}[/tex]

We get ,

[tex] \quad \longmapsto \qquad \:49 = (x) {}^{2} [/tex]

Applying square root on both sides :

[tex] \quad \longmapsto \qquad \: \sqrt{49} = \sqrt{(x) {}^{2} } [/tex]

We get ,

[tex] \quad \longmapsto \qquad \: \blue{ \underline{\boxed{\frak{7 \: cm = x}}}} \quad \bigstar[/tex]

  • Henceforth , length of x is 7 cm .

Verifying : -

We are verifying our answer by substituting all the values of hypotenuse , perpendicular and base in Pythagorean Theorem . So ,

  • ( 25 )² = ( 7 )² + ( 24 )²

  • 625 = 49 + 576

  • 625 = 625

  • L.H.S = R.H.S

  • Hence , Verified .

Therefore, our answer is correct .

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