I have absolutely no idea what to do here. Can someone break this down for me please?
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Answer:
Step-by-step explanation:
The task is to draw the parabola of the equation [tex]x^{2} -4x+4[/tex] on the given graph.
The first step we can take to doing this is to use the table on the left hand side to work out our x and corresponding y-values to use as plotting coordinates. To do this you want to substitute the given value for x which will give you a corresponding y-value.
E.g:
x | [tex]x^{2} -4x+4[/tex] | y
0 | [tex](0)^{2} -4(0)-4[/tex] | -4
Here we have gotten the coordinates (0, -4) so this will be a point on the graph.
Repeat with all other values on the table and you should get a bunch of dots which lead upwards in a curved line from a point. Extend the lines to form a parabola shape (A u-shape).
Once you have drawn the graph, label the parts.
Roots: The places where the line crosses the x-axis
Vertex: The lowest point of the parabola
Line of symmetry: The vertical line in which the parabola reflects/ is the same either side (Has equation x=_).
y-intercept: The point where the line crosses the y-axis.
Hope this helped!