Question

Can this please be worked out so I can have a better understanding?


Given the equation (picture 1)

and using the formula(picture 2)


find A, B, and C

Please if take your time to break it down for me so I can use it as a guide for the rest of the test!!! Thx <3 :)

Answer 1

Step-by-step explanation:

no, no, you use the equation to identify a, b and c.

then you use the formula with these values to get the solutions to the equation (the values of x for which the equation delivers 0).

always remember, a quadratic equation always has 2 solutions. sometimes at least one of them are not a real number, sometimes the 2 springs are equal, ...

x² - 4x - 2 = 0

a, b, c are the factors of the terms in x and the constant term.

so,

a = 1

b = -4

c = -2

x = (-b ± sqrt(b² - 4ac))/(2a)

x = (4 ± sqrt((-4)² - 4×1×-2))/(2×1) =

= (4 ± sqrt(16 + 8))/2 = (4 ± sqrt(24))/2 =

= (4 ± sqrt(4×6))/2 = (4 ± 2×sqrt(6)) / 2 =

= 2 ± sqrt(6)

x1 = 2 + sqrt(6)

x2 = 2 - sqrt(6)

Answer 2

Answer:

x = 4.45 and x=-0.45

Step-by-step explanation:

A = 1

B= -4

C = -2

= $\frac{-(-4) \sqrt{ (-4)^{2} -4 (1)(-2) } }{2(1)}$

= $\frac{4\sqrt{16+8} }{2}$

=  $\frac{4\sqrt{24} }{2}$

X = 4 + $\sqrt{24}$ / 2

x = 4.45

For x2

x= 4 - $\sqrt{24}$ / 2

x=-0.45