Question

Airline fares for a flight from Dallas to Austin are $30 for first class and $25 for tourist class. If a flight had 52 passengers who paid a total of $1360, how many first class passengers were on the trip?

Answer 1

Set up 2 equations.(x = number of people in first class, y = tourist class)

30x + 25y = 1360
x + y = 52

You have 2 equations and 2 unknown. You can solve them.
I like to use the substitution method 

Because    y = 52 - x
Then          30x + 25(52 - x) = 1360, solve for x.

30x + 1300 - 25x = 1360
5x = 60
x = 12

Use the x to solve y
30(12) + 25y = 1360
360 + 25y = 1360
25y = 1000
y = 40

Answer 2

The number of first class and tourist class passengers on the trip is 12 and 40 respectively

Given:

Cost of first class tickets = $30

Cost of tourists class tickets = $25

Total passengers = 52

Total cost = $1360

let

x = number of first class tickets

y = number of tourists class tickets

The equation:

x + y = 52 (1)

x + y = 52 (1)30x + 25y = 1360 (2)

multiply (1) by 25

25x + 25y = 1300 (3)

30x + 25y = 1,360 (2)

subtract (3) from (2) to eliminate y

30x - 25x = 1,360 - 1,300

5x = 60

x = 60/5

x = 12

substitute x = 12 into (1)

x + y = 52 (1)

12 + y = 52

y = 52 - 12

y = 40

Therefore, the number of first class and tourist class passengers on the trip is 12 and 40 respectively.

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