Question

pleaseeee pleaseee help mee with precal...One root of 2x2 + 8x + c = 0 is r1 = 1 + √5. Find r2.

Answer 1

if a root is a+√b then another is a-√b    because of quadatic formula



r2=1-√5

Answer 2

If one root of equation 2$x^{2}$+8x+c=0 is r1=1+$\sqrt{5}$ then the other root will be r2=7-$\sqrt{5}$.

What is equation?

Equation is relationship between two or more variables expressed in equal to form , Equations of two variables look like ax+by=c. It may be linear equation, quadratic equation and cubic equation.

How to find roots of equation?

We have been given one root of equation 2$x^{2}$+8x+c=11 be 1+$\sqrt{5}$ and we have to find the other root of the equation. We know that the standard equation from roots is $x^{2}$-sx+p=0 in which s is sum of roots and p is the product of roots.

When we compare the standard equation from the given equation we can find that sum of roots be 8.

let the other root be z such that:

z+1+$\sqrt{5}$=8

z=8-1+$\sqrt{5}$

=7+$\sqrt{5}$

Hence if one root of equation 2$x^{2}$+8x+c=0 is r1=1+$\sqrt{5}$ then the other root will be r2=7-$\sqrt{5}$.

Learn more about equation at https://brainly.com/question/2972832

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