Question

Miriam reduced a square photo by cutting 3 inches away from the length and the width so it will fit in her photo album. The area of the reduced photo is 64 square inches. In the equation (x – 3)2 = 64, x represents the side measure of the original photo. What were the dimensions of the original photo?

A. 11 inches by 11 inches
B. 5 inches by 5 inches
C. 3 + inches by 3 + inches
D. 3 inches by 3 inches

Answer 1

its A
because 64 divided by 8= 8 so I added the three originally taken away


hope it helps

Answer 2

Answer:

Option A is correct

11 inches by 11 inches

Step-by-step explanation:

Area of square (A) is given by:

$A = \text{Side} \times \text{Side}$

As per the statement:

Miriam reduced a square photo by cutting 3 inches away from the length and the width so it will fit in her photo album.

The area of the reduced photo is 64 square inches.

Given the equation:

$(x-3)^2 = 64$ where, x is the the side measure of the original photo.

Solve for x;

Take square root both sides we have;

$x-3 = \sqrt{64}$

⇒$x-3 = 8$

Add 3 to both sides we have;

x-3+3 = 8+3

⇒x = 11 inches

Therefore, the dimensions of the original photo were :  11 inches by 11 inches