Question

A solution with a ph of 5 has how many more protons in it than a solution with a ph of 7?

Answer 1

you're moving two steps from 7 to 5 (10 x10 = 100), so 100 times more protons would be the appropriate response.

Answer 2

Answer:

A solution with a pH of 5 has$9.9\times 10^{-6} M$ more protons in it than a solution with a pH of 7.

Explanation:

The pH of the solution is negative logarithm of  hydrogen ion concatenation in the aqueous solution. Mathematically written as:

$pH=-\log [H^+]$

1) A solution with a pH of 5 :

$5=-\log[H^+]$

$[H^+]=10^{-5} M$

2) A solution with a pH of 7 :

$7=-\log[H^+]'$

$[H^+]'=10^{-7} M$

$[H^+]>[H^+]'$

Difference in concentration of hydrogen ions or protons in both solutions:

$[H^+]-[H^+]'=10^{-5}M-10^{-7} M=9.9\times 10^{-6} M$