What is the midline of the function graphed below?
y = 1
y= 0.5
y = 0
y =2
![What is the midline of the function graphed below y 1 y 05 y 0 y 2 class=](https://us-static.z-dn.net/files/d0f/67d05f42115d6f88038821e9e326f55b.jpg)
Answer:
J
Step-by-step explanation:
42/2=21 or one triangles.
Using the Pythagorean Theorem A^2+B^2=C^2
441+?=625
[tex]\sqrt{184}[/tex] or about 13.6