Answer:
10m
explanation
[tex]looking \: at \: the \: diagram \\ horizontal \: lenght = 6m \\ vertical \: lenght = 8m \\ the \: \: lenght \: of \: the \: fencing \: can \: be \: calculated \\ using \: pythagoras \: theorem \\ let \: the \: lenght \: of \: the \: ladder = h \\ h {}^{2} { = 6}^{2} + 8 {}^{2} \\ h {}^{2} = 36 + 64 \\ h {}^{2} = 100 \\ square \: root \: bothsides \\ \sqrt{h {}^{2} } = \sqrt{100 } \\ h = 10 \\ therefore \: lenght \: of \: the \: ladder \: = 10m[/tex]
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