Find the vertex, axis of symmetry, and y-intercept of the quadratic function.
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Answer:
Step-by-step explanation:
The vertex form of quadratic function f(x) = ax² + bx + c:
f(x) = a(x - h)² + k
(h, k) - coordinates of a vertex
h = -b/2a
k = f(h)
We have f(x) = -x² + 8x - 4 ⇒ a = -1, b = 8, c = -4.
h = -8/(2 · (-1)) = -8/(-2) = 4
k = f(4) = -4² + 8 · 4 - 4 = -16 + 32 - 4 = 12
Vertex (4, 12)
Axis of symerty = h: x = 4
y - inrercept f(0) = c: -4
Answer:
See below ~
Step-by-step explanation:
Details of Graph