QR is the radius of R and PQ is the tangent to R. Find the value of x.
![QR is the radius of R and PQ is the tangent to R Find the value of x class=](https://us-static.z-dn.net/files/dc3/43bc3421e75d234bfb4a4f46041b679e.png)
Answer:
x = 39
Step-by-step explanation:
We know that PRQ is a right triangle, so we use the pythagorean theorem to solve the problem. The theorem states that a^2 + b^2 = c^2. Let's assume that the length of RP is c, the length of PQ is a and x is b. We plug the lengths into the equation and solve it:
80^2 + x^2 = 89^2
6400 +x^2 = 7921
x^2 = 1521
x = [tex]\sqrt{1521}[/tex]
x = 39