Question

What volume does 0.03 mol of N2 gas occupy at a temperature of 176°C and a pressure of 269 mm Hg?

Answer 1

Answer:

3.12 L

Explanation:

Given the R value that is supplied

      you will need to convert to atm from mm Hg    and C  to K

269 mm / 760 mm/atm = .354 atm

176 c = 449.15

PV = n RT

V = n RT / P    = .03 * .08206 * 449.15  / .354 = 3.12 L