Question

I need help with 3 and 4

Answer 1

Answer:

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( 3 )

the given figure resembles a rectangle !

now ,

$Area \: of \: rectangle = length \times breadth \\ \\ given \: - \: length = 12 \: ft \\ \therefore \:breadth = x \: ft \\ \\ Area = 108 \: ft {}^{2} \\ \\ \implies \: length \times breadth = 108 \: ft {}^{2} \\ \\ \implies \: x \times 12 = 108 \\ \\ \implies \: x = \cancel\frac{108}{12} \\ \\ \bold\red{\implies \: x = 9 \: ft}$

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( 4 )

the given figure resembles a parallelogram!

$Area \: of \: parallelogram = height \times base \\ \\ \implies \: height = x \: cm\\ \\ \implies \: base = 16 \: cm \\ \\ \: Area \: = 96 \: cm {}^{2} \\ \\ \implies \: x \times 16 = 96 \\ \\ \implies \: x = \cancel\frac{96}{16} \\ \\ \bold\red{\implies \: x = 6 \: cm}$

hope helpful :D

Answer 2

$\huge \underbrace \mathfrak \red{Answer}$

To find :-

To get the value of 'di in figure 3 and 4.

Figure 3

• According to the figure, we know that it is a quadrilateral.
• It's all sides are at 90°.
• So we can assume that it can be rectangle.
• In the figure, length of one side is given and area of figure is given and we have the length of another side.

Solution :-

Area of rectangle = length × width

area = 108 ft², length = 12 ft, width = x

$108 = 12 \times x \\ \frac{108}{12} = x \\ 9 = x$

• Therefore, the value of x in this figure is 9 ft.

Figure 4

• According to figure, we finds out that it is quadrilateral as it has 4 sides.
• It has all parallel sides.
• We can assume that it is parallelogram as the sides which are facing each other are parallels.
• And here value of one side is given which is base and area is given, we have to find here is height.

Solution :-

Area of parallelogram = base × height

Area = 96 cm², base = 16 cm, height = x

$96 = 16 \times x \\ \frac{96}{16} = x \\ 6 = x$

• Therefore, the value of x is 6 cm.