The length of a rectangle is five time it’s width. If the perimeter of a rectangle is 84ft, find its area
![The length of a rectangle is five time its width If the perimeter of a rectangle is 84ft find its area class=](https://us-static.z-dn.net/files/d14/91119a9efb9464b0674f5927d8f63356.png)
Answer:
Area = 245 ft
(Width
Step-by-step explanation:
l = 5w
Where l is length and w is width.
We also know that the perimeter is 84 ft, so:
2l + 2w = 84
Now we can plug in 5w for l since we found the equality earlier:
2(5w) + 2w = 84
and then solve for w:
10w + 2w = 84
12w = 84
w = 7
so
l = 5 × 7
l = 35
The length is 35 and width is 7 so
the area of the rectangle is
[tex]7 \times 35 = 245ft [/tex]