Question

A 2-kg bowling ball rolls at a speed of 5 m/s on the roof of the building that is 40 tall.

Circle one: KE / GPE / both

Answer 1

the KE can be solve using the formula:
ke = 0.5 mv^2
where m is the mass of the object
v is the velocity
ke = 0.5 ( 2 kg ) ( 5 m/s)^2
ke = 25 J

the GPE can be solved using the formula:
GPE = mgh
where m is the mass
g is the acceleration due to gravity ( 9.81 m/s^2)
h is the height

GPE = ( 4 kg)(9.81 m/s^2)( 40 m)
GPE = 392.4 J

Answer 2

Answer:

The ball has both KE (kinetic energy) and GPE (gravitational potential energy)

Explanation:

- The KE of the ball is given by:

$KE=\frac{1}{2}mv^2$

where

m = 2 kg is the mass of the ball

v = 5 m/s is the speed of the ball

Substituting into the equation, we find

$KE=\frac{1}{2}(2 kg)(5 m/s)^2=25 J$

- The GPE of the ball is given by:

$GPE=mgh$

where

m = 2 kg is the mass

g = 9.8 m/s^2 is the gravitational acceleration

h = 40 m is the heigth of the ball

Substituting into the equation, we find

$GPE=(2 kg)(9.8 m/s^2)(40 m)=784 J$

So, the ball has both KE and GPE.