Question

a 10. kg ball thrown into the air. it is going 3.0 m/s when thrown. how much potential energy will it have at the top?

Answer 1

Answer:

45 j

Explanation:

At the top, the KE will have been converted to PE

KE = 1/2 mv^2 =PEat-top = 1/2 10 *3^9 = 45 j