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Equation of the circumference whose center is at [tex]\mathsf{C(0,\,0)}[/tex] and whose radius is [tex]\mathsf{r=5:}[/tex]
[tex]\mathsf{(x-x_C)^2+(y-y_C)^2=r^2}\\\\ \mathsf{(x-0)^2+(y-0)^2=5^2}\\\\ \mathsf{x^2+y^2=25}[/tex]
We are looking for the point that satisfies the equation above.
• Testing [tex]\mathsf{(-3,\,4):}[/tex]
[tex]\mathsf{(-3)^2+4^2}\\\\ \mathsf{9+16}\\\\ \mathsf{25\qquad\quad\checkmark}[/tex]
The point [tex]\mathsf{(-3,\,4)}[/tex] lies in the circumference.
• Testing [tex]\mathsf{(1,\,-2):}[/tex]
[tex]\mathsf{1^2+(-2)^2}\\\\ \mathsf{1+4}\\\\ \mathsf{5\ne 25\qquad\quad\diagup\hspace{-9}\diagdown}[/tex]
The point [tex]\mathsf{(1,\,-2)}[/tex] doesn't lie in the circumference.
• Testing [tex]\mathsf{(\sqrt{5},\,\sqrt{5}):}[/tex]
[tex]\mathsf{(\sqrt{5})^2+(\sqrt{5})^2}\\\\ \mathsf{5+5}\\\\ \mathsf{10\ne 25\qquad\quad\diagup\hspace{-9}\diagdown}[/tex]
So, the point [tex]\mathsf{(\sqrt{5},\,\sqrt{5})}[/tex] doesn't lie in the circumference either.
Answer: (–3, 4).
I hope this helps. =)
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Equation of the circumference whose center is at [tex]\mathsf{C(0,\,0)}[/tex] and whose radius is [tex]\mathsf{r=5:}[/tex]
[tex]\mathsf{(x-x_C)^2+(y-y_C)^2=r^2}\\\\ \mathsf{(x-0)^2+(y-0)^2=5^2}\\\\ \mathsf{x^2+y^2=25}[/tex]
We are looking for the point that satisfies the equation above.
• Testing [tex]\mathsf{(-3,\,4):}[/tex]
[tex]\mathsf{(-3)^2+4^2}\\\\ \mathsf{9+16}\\\\ \mathsf{25\qquad\quad\checkmark}[/tex]
The point [tex]\mathsf{(-3,\,4)}[/tex] lies in the circumference.
• Testing [tex]\mathsf{(1,\,-2):}[/tex]
[tex]\mathsf{1^2+(-2)^2}\\\\ \mathsf{1+4}\\\\ \mathsf{5\ne 25\qquad\quad\diagup\hspace{-9}\diagdown}[/tex]
The point [tex]\mathsf{(1,\,-2)}[/tex] doesn't lie in the circumference.
• Testing [tex]\mathsf{(\sqrt{5},\,\sqrt{5}):}[/tex]
[tex]\mathsf{(\sqrt{5})^2+(\sqrt{5})^2}\\\\ \mathsf{5+5}\\\\ \mathsf{10\ne 25\qquad\quad\diagup\hspace{-9}\diagdown}[/tex]
So, the point [tex]\mathsf{(\sqrt{5},\,\sqrt{5})}[/tex] doesn't lie in the circumference either.
Answer: (–3, 4).
I hope this helps. =)