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Which of the following points lies on the circle whose center is at the origin and whose radius is 5?

(-3, 4)
(1, -2)
(√5,√5)

Respuesta :

lukyo
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Equation of the circumference whose center is at [tex]\mathsf{C(0,\,0)}[/tex] and whose radius is [tex]\mathsf{r=5:}[/tex]

[tex]\mathsf{(x-x_C)^2+(y-y_C)^2=r^2}\\\\ \mathsf{(x-0)^2+(y-0)^2=5^2}\\\\ \mathsf{x^2+y^2=25}[/tex]


We are looking for the point that satisfies the equation above.


•  Testing [tex]\mathsf{(-3,\,4):}[/tex]

[tex]\mathsf{(-3)^2+4^2}\\\\ \mathsf{9+16}\\\\ \mathsf{25\qquad\quad\checkmark}[/tex]


The point [tex]\mathsf{(-3,\,4)}[/tex] lies in the circumference.


•  Testing [tex]\mathsf{(1,\,-2):}[/tex]

[tex]\mathsf{1^2+(-2)^2}\\\\ \mathsf{1+4}\\\\ \mathsf{5\ne 25\qquad\quad\diagup\hspace{-9}\diagdown}[/tex]


The point [tex]\mathsf{(1,\,-2)}[/tex] doesn't lie in the circumference.


•  Testing [tex]\mathsf{(\sqrt{5},\,\sqrt{5}):}[/tex]

[tex]\mathsf{(\sqrt{5})^2+(\sqrt{5})^2}\\\\ \mathsf{5+5}\\\\ \mathsf{10\ne 25\qquad\quad\diagup\hspace{-9}\diagdown}[/tex]


So, the point [tex]\mathsf{(\sqrt{5},\,\sqrt{5})}[/tex] doesn't lie in the circumference either.



Answer:  (–3,  4).


I hope this helps. =)

Answer:

(-3,4)

Step-by-step explanation:

sos

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