Question

i need help! what is the volume of a 2.0 m solution of an acid needed to neutralize a 3.0 m solution of a 250 ml base?

Answer 1

Using the titration formula, we know that:

(2.0 M)(volume of acid)=(3.0 M)(250 mL)

volume of acid = (3.0)(250)/(2.0) = 375 mL